Show that A(-3, 2), B (-5, -5), C (2, -3) and D(4, 4) are the vertices of a rhombus.
Given points are A(-3, 2), B (-5, -5), C (2, -3) and D(4, 4)

By distance formula,
XY = ![]()
For AB ,
AB = ![]()
= ![]()
=
units
For BC ,
BC = ![]()
= ![]()
=
units
For CD,
CD = ![]()
= ![]()
=
units
For AD ,
AB = ![]()
= ![]()
=
units
Here we can observe that all lengths of □PQRS are equal.
Now for diagonal AC,
AC = ![]()
= ![]()
=
units
Now for diagonal BD,
BD = ![]()
= ![]()
=
units
Here in □ABCD, diagonals are unequal.
We know that a quadrilateral whose all sides are equal and diagonals are unequal, it is a rhombus.
Hence, our □ABCD is rhombus .