A (3, 2) and B (-2, 1) are two vertices of a triangle ABC whose centroid G has the coordinates (5/3, - 1/3). Find the coordinates of the third vertex C of the triangle.

Let the vertex of the triangle be A(3, 2), B(-2, 1) and C(x, y)


Let the centroid be G(, ), as it is given that centroid is given at origin.



We know that centroid of a triangle for (x1 , y1), (x2 , y2) and (x3 , y3) is


G(x, y) = ( , )


For given coordinates A(3, 2), B(-2, 1) and C(x, y)


(, ) = , )


Solving for x and y,


-3 + 2 +x =5 and 2 + = -1


x = 4 and y = -4


Hence, the coordinate of third vertex is C(4, -4).


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