In Δ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:
(i) Sin A, Cos A
(ii) Sin C, Cos C
Applying Pythagoras theorem for ΔABC, we obtain
AC2 = AB2 + BC2
= (24)2 + (7)2
= (576 + 49)
= 625 cm2
∴ AC = 
= 25 cm
(i) Sin A = 
= 
Cos A = 
= 
(ii) Sin C = 
= 
Cos C = 
= 
62