In Δ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine:

(i) Sin A, Cos A


(ii) Sin C, Cos C

Applying Pythagoras theorem for ΔABC, we obtain

AC2 = AB2 + BC2


= (24)2 + (7)2


= (576 + 49)


= 625 cm2


AC =


= 25 cm



(i) Sin A =


=


Cos A =


=


(ii) Sin C =


=



Cos C =


=


24