If sin calculate Cos A and tan A

Let ΔABC be a right-angled triangle, right-angled at point B


Given that,


Sin A =



Let BC be 3k. Therefore, AC will be 4k, where k is a positive integer.


Applying Pythagoras theorem in ΔABC, we obtain


AC2 = AB2 + BC2


(4k)2 = AB2 + (3k)2


16k2 - 9k2 = AB2


7k2 = AB2


AB = k


Cos A =


= =


Tan A =


= =


18