Given 15 cot A = 8, find sin A and sec A
Consider a right-angled triangle, right-angled at B
Cot A = 
It is given that,
Cot A = 
Let AB be 8k. Therefore, BC will be 15k, where k is a positive integer.
Applying Pythagoras theorem in ΔABC, we obtain
AC2 = AB2 + BC2
= (8k)2 + (15k)2
= 64k2 + 225k2
= 289k2
AC = 17k
Sin A = 
= 
Sec A = 
= 
27