If 3 cot A = 4, check whether
or not
It is given that 3cot A = 4
Or, cot A = ![]()
Consider a right triangle ABC, right-angled at point B

Cot A = ![]()
= ![]()
If AB is 4k, then BC will be 3k, where k is a positive integer
In ΔABC,
(AC)2 = (AB)2 + (BC)2
= (4k)2 + (3k)2
= 16k2 + 9k2
= 25k2
AC = 5k
Cos A = ![]()
= ![]()
= ![]()
Sin A = ![]()
= ![]()
= ![]()
Tan A = ![]()
= ![]()
= ![]()
1 – tan2A/1 + tan2A = 
= 
=
= ![]()
Cos2A – Sin2A =
2 –
2
= ![]()
= ![]()
Therefore,
1 – tan2A/1 + tan2A = Cos2A – Sin2A