If and find A and B

tan (A + B) =

tan (A + B) = tan 60^{o}

A + B = 60^{O} (i)

tan (A – B) =

tan (A - B) = tan 30^{O}

A - B = 30 (ii)

On adding both equations, we obtain

2 A = 90

⇒ A = 45

From equation (i), we obtain

45 + B = 60

B = 15^{o}

Therefore, ∠A = 45° and ∠B = 15°

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