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If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A
tan 2A = cot (90° – 2A)
Hence,
90° – 2A = A – 18°
108° – 2A = A
3A = 108°
A = 108/3 = 36°
Evaluate:
(i)
(ii)
(iii) Cos 48° – sin 42°
(iv) Cosec 31° – sec 59°
Show that:
(i) tan 48° tan 23° tan 42° tan 67° = 1
(ii) cos 38° Cos 52° – sin 38° sin 52° = 0
If tan A = cot B, prove that A + B = 90°
If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A
If A, B and C are interior angles of a triangle ABC, then show that
Express sin 67° + Cos 75° in terms of trigonometric ratios of angles between 0° and 45°