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If tan A = cot B, prove that A + B = 90°
tan A = cot (90°- A) = cot B
Therefore,
90° - A = B
A + B = 90°
Hence proved
Evaluate:
(i)
(ii)
(iii) Cos 48° – sin 42°
(iv) Cosec 31° – sec 59°
Show that:
(i) tan 48° tan 23° tan 42° tan 67° = 1
(ii) cos 38° Cos 52° – sin 38° sin 52° = 0
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A
If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A
If A, B and C are interior angles of a triangle ABC, then show that
Express sin 67° + Cos 75° in terms of trigonometric ratios of angles between 0° and 45°