What is the measure of each of the equal angles of a right-angled isosceles triangle?

Here given triangle is isosceles right angled triangle.



So let our triangle be ∆ABC, right angled at A.


A = 90°


Here, AB = AC, as our given triangle is isosceles triangle.


Hence, base angles, B and C are equal.


Also, We know that,


Sum of all angles in any triangle = 180°


A + B + C = 180°


90° + 2 B = 180°


2B = 90°


B = 45°


Hence the measure of each of the equal angles of a right-angled isosceles triangle is 45°


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