What is the measure of each of the equal angles of a right-angled isosceles triangle?
Here given triangle is isosceles right angled triangle.
So let our triangle be ∆ABC, right angled at A.
∴ ∠A = 90°
Here, AB = AC, as our given triangle is isosceles triangle.
Hence, base angles, ∠B and ∠C are equal.
Also, We know that,
Sum of all angles in any triangle = 180°
∴ ∠A + ∠B + ∠C = 180°
90° + 2 ∠B = 180°
2∠B = 90°
∠B = 45°
Hence the measure of each of the equal angles of a right-angled isosceles triangle is 45°