In the adjoining figure, X and Y are respectively two points on equal sides AB and AC of ∆ABC such that AX=AY. Prove that CX=BY.
Here it is given that AX = AY.
Now in ∆CXA and ∆BYA,
AX = AY
∠XAC = ∠YAB … Same angle or common angle.
AC = AB … given condition Hence by SAS property of congruency,
∆CXA ≅ ∆BYA
Hence by cpct, we conclude that,
CX = BY