In the adjoining figure, X and Y are respectively two points on equal sides AB and AC of ∆ABC such that AX=AY. Prove that CX=BY.

Here it is given that AX = AY.


Now in ∆CXA and ∆BYA,


AX = AY


XAC = YAB … Same angle or common angle.


AC = AB … given condition Hence by SAS property of congruency,


∆CXA BYA


Hence by cpct, we conclude that,


CX = BY


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