ABC is a triangle in which AB=AC. If the bisectors of ∠B and ∠C meet AC and AB in D and E respectively, prove that BD=CE.
Given: AB=AC and BD and AB are angle bisectors of ∠B and ∠C
To prove: BD = CE
Proof:
In ∆ABD and ∆ACE,
∠ABD = ∠B
And ∠ACE = ∠C
But ∠B = ∠C as AB = AC … As in isosceles triangle, base angles are equal
∠ABD = ∠ACE
AB = AC
∠A = ∠A
Thus by ASA property of congruence,
∆ABD ≅ ∆ACE
Hence, we know that, corresponding parts of the congruent triangles are equal
∴ BD = CE