Prove that median from the vertex of an isosceles triangle is the bisector of the vertical angle.
Given: ∆ABC is isosceles triangle where AB = AC and BD = DC
To prove: ∠BAD = ∠DAC
Proof:
In ∆ABD and ∆ADC
AB = AC …given
BD = DC …given
AD = AD … common side
Thus by SSS property of congruence,
∆ABD ≅ ∆ADC
Hence, we know that, corresponding parts of the congruent triangles are equal
∠BAD = ∠DAC