The base of a right – angles triangle measures 48cm and its hypotenuse measures 50cm. Find the area of the triangle.

Given that,

Base = BC = 48 cm

Hypotenuse = AC = 50 cm

Let us assume AB = x cm

By using Pythagoras theorem, we get

AC^{2} = AB^{2} + BC^{2}

Putting the value of BC, AC and AB we get:

50^{2} = x^{2} + 48^{2}

x^{2} = 50^{2} - 48^{2}

x^{2} = 2500 – 2304

x^{2} = 196

x =

x = 14 cm

We know that,

Area of right angle triangle =

=

= 24 × 14

= 336 cm^{2}

14