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Find the area of a parallelogram ABCD in which AB = 28cm, BC = 26cm and diagonal AC = 30 cm.
Let the sides of the triangle ABC be:
a = 26 cm
b = 30 cm
And
c = 28 cm
Let us find out the value of s
We know that,
s =
=
=
= 42 cm
We know that,
Area of triangle ABC =
=
=
=
=
= 14 × 3 × 4 × 2
= 336 cm2
We know that,
In a parallelogram, the diagonal divides the parallelogram in two equal area
Therefore,
Area of quadrilateral ABCD = Area of triangle ABC + Area of triangle ACD
= Area of triangle ABC × 2
= 336 × 2
= 672 cm2