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Find the area of the parallelogram ABCD in which AB = 14 cm, BC = 10 cm and AC = 16cm. [ Given = 1.73]
According to the question,
In order to find the area of quadrilateral ABCD,
At first,
Let us consider triangle ABC,
Say,
a = 10 cm, b = 16 cm and c = 14 cm
Now,
Semi perimeter of ΔABC, s =
=
=
= 20 cm
Now,
Area of ΔABC =
=
=
= 40√3 cm2
We know that, the diagonal of a parallelogram divides it into two triangles of equal areas.
Hence,
Area of quadrilateral ABCD = Area of ΔABC + Area of ΔACD
= Area of ΔABC × 2
= 40√3 × 2
= 80√3 cm2
= 138.4 cm2