Given :- Right trapezium

RS = 8 cm

PT = 8cm

TQ = 8 cm

RQ = 17 cm

Here PQ = PT + TQ = 8 + 8 = 16

We know that area of trapezium is x (sum of parallel sides) x height

That is x (AB + DC) x RT

Consider TQR

By Pythagoras theorem

RQ² = TQ² + RT²

17² = 8² + RT²

RT² = 17 ² - 8² = 289 – 64 = 225

RT = 15 cm

Area of trapezium = x (RS + PQ) x RT

= x (8 + 16) x 15 = 180 cm²

Area of trapezium PQRS = 180cm²