In the given figure, a circle with center is given in which a diameter bisects the chord at a point such that and Find the radius of the circle.

Let radius OA = OB = OD = r


DE = 8 cm


OE = OB – BE


OE = r – 4



In triangle ODE,


OD2 = DE2 + OE2


r2 = 82 + (r - 4)2


r2 = 64 + r2 + 16 - 8r


8r = 80


r = 10 cm


Hence, radius of circle = 10 cm.


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