In the given figure, a circle with center is given in which a diameter
bisects the chord
at a point
such that
and
Find the radius of the circle.
Let radius OA = OB = OD = r
DE = 8 cm
OE = OB – BE
⇒ OE = r – 4
In triangle ODE,
OD2 = DE2 + OE2
⇒ r2 = 82 + (r - 4)2
⇒ r2 = 64 + r2 + 16 - 8r
⇒ 8r = 80
⇒ r = 10 cm
Hence, radius of circle = 10 cm.