In the adjoining figure, is perpendicular to the chord of a circle with center If is a diameter, show that and
Given ODAB
In triangle ABC,
D is the mid-point of AB
∴ AD = DB
O is the mid-point of BC
∴ OC = OB
We say, AC||OD
(1/2) AC = OD [Mid-point theorem in triangle ABC]
⇒ AC = 2 × OD Proved.