Prove that the diameter of a circle perpendicular to one of the two parallel chords of a circle is perpendicular to the other and bisects it.
∠PFD = ∠PEB [equal to 90°]
∴PF
CD and OF
CD
We know that the perpendicular from the center of a circle to chord, bisect the chord.
Therefore,
CF = FD Proved.
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