If a diameter of a circle bisects each of the two chords of a circle then prove that the chords are parallel.
Let AB and CD are two chords of a circle with center O.
Diameter POQ bisect s them at L and M.
Then,
OL
AB and OM
CD
∴ ∠ALM = ∠LMD
∴ AB||CD [Alternate angles]
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