In the adjoining figure, is a chord parallel to diameter of the circle with center If calculate

CAD and CBD are in the segment BD.


CAD = CBD [Angles in the same segment of a circle]


CAD = 60°


In triangle ACD,


CAD + ADC + ACD = 180°[Sum of angles of triangle]


60° + 90° + ACD = 180°


150° + ACD = 180°


ACD = 30°


CDE = ACD = 30°[Alternate angles]


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