In the given figure, is the center of a circle in whichand Find (i) (ii)

(i)


OB = OC [Radius]


OBC = OCB = 55°


In triangle OCB,


OBC + OCB + BOC = 180°[Sum of angles of triangle]


55° + 55° + BOC = 180°


110° + BOC = 180°


BOC = 70°


(ii)


OA = OB [Radius]


OBA = OAB = 20°


In triangle AOB,


OBA + OAB + AOB = 180°[Sum of angles of triangle]


20° + 20° + AOB = 180°


40° + AOB = 180°


AOB = 140°


AOC = AOB - BOC


AOC = 140° - 70°


AOC = 70°


12