In the given figure, is a cyclic quadrilateral whose diagonals intersect at
such that
and
Find (i)
(ii)
(i)
∠BAC = ∠BDC = 40°[Angles in the same segment]
In triangle BCD,
∠BCD + ∠DBC + ∠BDC = 180°[Sum of angles of triangle]
⇒ ∠BCD + 60° + 40° = 180°
⇒ ∠BCD + 100° = 180°
⇒ ∠BCD = 80°
(ii)
∠CAD = ∠CBD [Angles in the same segment]
⇒ ∠CAD = 40°