In the given figure, is a diameter and is a cyclic quadrilateral. If find

In cyclic quadrilateral PQRS,


PSR + PQR = 180°[Opposite angles]


150° + PQR = 180°


PQR = 30°


In triangle PQR,


RPQ + PQR + PRQ = 180°[Sum of angles of triangle]


RPQ + 30° + 90° = 180°


RPQ + 120° = 180°


RPQ = 60°


2