In the adjoining figure, is a cyclic quadrilateral in which
and
Find
ABCD is a cyclic quadrilateral
∴ ∠BCD + ∠BAD = 180°[Opposite angle of a cyclic quadrilateral are supplementary]
⇒ 100° + ∠BAD = 180°
⇒ ∠BAD = 80°
In triangle ABD,
∠ADB + ∠ABD + ∠BAD = 180°[Sum of angles of triangle]
⇒ ∠ADB + 50° + 80° = 180°
⇒ ∠ADB + 130° = 180°
⇒ ∠ADB = 50°