In the adjoining figure, is a cyclic quadrilateral in which and Find

ABCD is a cyclic quadrilateral


BCD + BAD = 180°[Opposite angle of a cyclic quadrilateral are supplementary]


100° + BAD = 180°


BAD = 80°


In triangle ABD,


ADB + ABD + BAD = 180°[Sum of angles of triangle]


ADB + 50° + 80° = 180°


ADB + 130° = 180°


ADB = 50°


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