Two supplementary angles are in the ratio 3:2 Find the angles.
108°, 72°
Let angle = X
Supplementary of X = 180° – X
According to question,
X : 180° – X = 3 : 2
⇒ X / (180° – X) = 3 / 2
⇒ 2X = 3(180° – X)
⇒ 2X = 540° – 3X
⇒ 2X + 3X = 540°
⇒ 5X = 540°
⇒ X = 108°
Therefore angle = 108°
And its supplement = 180° – 108° = 72°