=130°,=50°, =130°

Given AB and CD intersect a O

Therefore, = _____________________ (i)

And ∠BOC = ∠AOD _____________________ (ii)

=50°

Therefore, =50° from equation (i)

AOB is a straight line,

⇒ + = 180°

⇒ 50° + = 180°

⇒ = 180° - 50°

⇒ = 130°

∠AOD = ∠BOC = 130° from equation (ii)