In the given figure, AB is a mirror; PQ is the incident ray and QR, the reflected ray. If =112°, Find .

Question

In the given figure, AB is a mirror; PQ is the incident ray and QR, the reflected ray. If =112&#xB0;, Find .

Philoid · Accepted Answer

34°

Angle of incidence =angle of reflection.

Therefore, ∠PQA = ∠BQR _____________________ (i)

⇒ ∠BQR + ∠PQR + ∠PQA = 180°[Because AQB is a straight line]

⇒ ∠BQR + 112° + ∠PQA = 180°

⇒ ∠BQR + ∠PQA = 180° - 112°

⇒ ∠PQA + ∠PQA = 68° [from equation (i)]

⇒ 2 ∠PQA = 68°

⇒ ∠PQA = 34°