In the adjoining figure, AB ||CD are cut by a transversal t at E and F respectively. If =70°, Find measure of each of the remaining marked angles.

=110°, =70°,=110°, =70°,=110°,=70°, =110°


Given AB ||CD are cut by a transversal t at E and F respectively.


And ∠1 = 70°


∠1 = ∠3 = 70° [Opposite angles]


∠5 = ∠1 = 70° [Crossponding angles]


∠3 = ∠7 = 70° [Crossponding angles]


∠1 + ∠2 = 180° [Because AB is a straight line]


⇒ 70° + ∠2 = 180°


⇒ ∠2 = 110°


∠4 = ∠2 = 110° [Opposite angles]


∠6 = ∠2 = 110° [Crossponding angles]


∠8 = ∠4 = 110° [Crossponding angles]


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