In the given figure, AB ||CD. Find the value of x.
X=45
Given AB||CD
Therefore, ∠BAC + ∠ACD = 180°
⇒ 75° + ∠ACD = 180°
⇒ ∠ACD = 105°_________________ (i)
∠ACD = ∠ECF = 105°[Opposite angles]
In triangle CEF,
⇒ ∠CEF + ∠EFC + ∠FCE = 180°
⇒ x + 30° + 105° = 180°
⇒ x + 135° = 180°
⇒ x = 45°