In the given figure, AB ||CD. Find the value of x.

X=45


Given AB||CD


Therefore, BAC + ACD = 180°


75° + ACD = 180°


ACD = 105°_________________ (i)


ACD = ECF = 105°[Opposite angles]


In triangle CEF,


CEF + EFC + FCE = 180°


x + 30° + 105° = 180°


x + 135° = 180°


x = 45°


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