X=60, y=60, z=70, t=70

Given AB||CD and EF||GH

x = 60° [Opposite angles]

y = x = 60°[Alternate angles]

∠PQS = ∠APR = 110°[Crossponding angles]

∠PQS = ∠PQR + y = 110°_____________ (i)

For AB straight line,

⇒ y + z + ∠PQR = 180°

⇒ z + 110° = 180°[From equation (i)]

⇒ z = 70°

AB||CD

Therefore,

t = z = 70°[Because alternate angles]