=50°, =58°^,=72°

Given,

+= 108° ___________________ (i)

+ = 130° ___________________ (ii)

We know that sum of angles of triangle = 180°

∠A + ∠B + ∠C = 180° [Sum of angles]

∠A + 130°= 180° [From equation (ii)]

⇒ ∠A = 50°

Value of ∠A = 50° put in equation (i),

+ = 108°

⇒ 50° + = 108°

⇒ = 58°

Value of ∠B = 58° put in equation (ii),

+ = 130°

⇒ 58° + = 130°

⇒ = 72°