=67°, =41°, =89°

Given,

+= 125° ___________________ (i)

+ = 113° ___________________ (ii)

We know that sum of angles of triangle = 180°

∠A + ∠B + ∠C = 180° [Sum of angles]

∠A + 113°= 180° [From equation (ii)]

⇒ ∠A = 67°

Value of ∠A = 50° put in equation (i),

+ = 125°

⇒ 67° + = 108°

⇒ = 41°

Value of ∠B = 41° put in equation (ii),

+ = 130°

⇒ 41° + = 130°

⇒ = 89°