In the given figure, side BC of 
ABC is produced to D. If 
=128° and 
=43°,Find 
and 
.
∠BAC = 85°, ∠ACB = 52°
Given, 
=128° and 
=43°
In triangle ABC,
∠ACB + ∠ACD = 180° [Because BCD is a straight line]
⇒ ∠ACB + 128° = 180°
⇒ ∠ACB = 52°
∠ABC + ∠ACB + ∠BAC = 180° [Sum of angles of triangle ABC]
⇒ 43° + 52° + ∠BAC = 180°
⇒ ∠BAC = 85°
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