In the given figure, the side BC of has been produced on both sides-on the left to D and on the right to E. If
=106° and
=118°, Find the measure of each angle of the triangle.
74°, 62°, 44°
Given, =106° and
=118°
∠ABD + ∠ABC = 180° [Because DC is a straight line]
⇒ 106° + ∠ABC = 180°
⇒ ∠ABC = 74°_______________ (i)
∠ACB + ∠ACE = 180° [Because BE is a straight line]
⇒ ∠ACB + 118° = 180°
⇒ ∠ACB = 62°_______________ (ii)
Now, triangle ABC
∠ABC + ∠ACB + ∠BAC = 180° [Sum of angles of triangle]
⇒ 74° + 62° + ∠BAC = 180° [From equation (i) and (ii)]
⇒ ∠BAC = 44°