In the given figure, ABC is a triangle in which::=3:2:1 and AC CD. Find the measure of.
60°
Given, ::= 3:2:1 and AC CD
Let, ∠A = 3a
∠B = 2a
∠C = a
In triangle ABC,
∠A + ∠B + ∠C = 180°[Sum of angles of triangle]
⇒ 3a + 2a + a = 180°
⇒ 6a = 180°
⇒ a = 30°
Therefore, ∠C = a = 30°
Now,
∠ACB + ∠ACD + ∠ECD = 180°[Sum of angles of triangle]
⇒ 30° + 90° + ∠ECD = 180°
⇒ ∠ECD = 60°