Find the zero of the polynomial:
(i) P(x)=x-5
(ii) q(x)=x+4
(iii) p(t)=2t-3
(iv) f(x)=3x+1
(v) g(x)=5-4x
(vi) h(x)=6x-1
(vii) p(x)=ax + b,a≠0
(viii) q(x) = 4x
(ix) p(x)=ax,a≠0
(i) At first,
In order to find the zero of the polynomial we will,
Put p(x) = 0
Now,
We have,
P(x)=x-5
0 = x – 5
x = 5
Hence, 5 is the zero of the given polynomial.
(ii) At first,
In order to find the zero of the polynomial we will,
Put q(x) = 0
Now,
We have,
q(x)=x+4
0 = x + 4
x = - 4
Hence, -4 is the zero of the given polynomial.
(iii) At first,
In order to find the zero of the polynomial we will,
Put p(t) = 0
Now,
We have,
P(t)= 2t - 3
0 = 2t – 3
2t = 3
t = 3/2
Hence, 3/2 is the zero of the given polynomial.
(iv) At first,
In order to find the zero of the polynomial we will,
Put f(x) = 0
Now,
We have,
f(x)= 3x + 1
0 = 3x + 1
3x = -1
x =
Hence, -1/3 is the zero of the given polynomial.
(v) At first,
In order to find the zero of the polynomial we will,
Put g(x) = 0
Now,
We have,
g(x)= 5 – 4x
0 = 5 – 4x
4x = 5
x = 5/4
Hence, 5/4 is the zero of the given polynomial.
(vi) At first,
In order to find the zero of the polynomial we will,
Put h(x) = 6x - 1
Now,
We have,
h(x)= 6x- 1
0 = 6x – 1
6x = 1
x = 1/6
Hence, 1/6 is the zero of the given polynomial.
(vii) At first,
In order to find the zero of the polynomial we will,
Put p(x) = 0
Now,
We have,
p(x)= ax + b
0 = ax + b
ax = -b
x = (-b)/a
Hence, (-b)/a is the zero of the given polynomial.
(viii) At first,
In order to find the zero of the polynomial we will,
Put q(x) = 0
Now,
We have,
q(x)= 4x
0 = 4x
x = 0
Hence, 0 is the zero of the given polynomial.
(ix) At first,
In order to find the zero of the polynomial we will,
Put p(x) = 0
Now,
We have,
p(x)= ax
0 = ax
x = 0
Hence, 0 is the zero of the given polynomial.