is divided by (x-1)
Let, f(x) = x3 – 6x2 + 9x + 3
Now,
As per the question,
x – 1 = 0
x = 1
Using Remainder theorem,
We know that when f(x)is divided by (x – 1), the remainder so obtained will be f(1).
Hence,
f(1) = (1)3 – 6(1)2 + 9(1) + 3
= 1 – 6 + 9 + 3
= 13 – 6
= 7
Therefore,
The required remainder is 7
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