is divided by (x-3)
Let, f(x) = 2x3 – 5x2 + 9x - 8
Now,
As per the question,
x – 3 = 0
x = 3
Using Remainder theorem,
We know that when f(x)is divided by (x – 3), the remainder so obtained will be f(3).
Hence,
f(3) = 2(3)3 – 5(3)2 + 9(3) - 8
= 2(27) – 5(9) + 27 - 8
= 54 – 45 + 19
= 28
Therefore,
The required remainder is 28