is divided by (x+3)
Let, f(x) = 2x4 + 6x3 + 2x2 + x - 8
Now,
As per the question,
x - 3 = 0
x = 3
Using Remainder theorem,
We know that when f(x)is divided by (x – 3), the remainder so obtained will be f(3).
Hence,
f(3) = 2(3)4 + 6(3)3 + 2(3)2 + 3 - 8
= 2(81) + 6(27) +18 – 5
= 18 - 11
= 7
Therefore,
The required remainder is 7.
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