From the factor theorem, we have (x – 1) is the factor of f(x) if f(1) = 0 Here, we have f(1) = 2 × 1 4 + 9 × 1 3 + 6 × 1 2 – 11 × 1 – 6 = 2 + 9 + 6 – 11 – 6 = 17 – 17 = 0 Therefore, (x – 1) is the factor of (2x 4 + 9x 3 + 6x 2 – 11x – 6)

(x-1) is a factor of

From the factor theorem, we have

(x – 1) is the factor of f(x) if f(1) = 0

Here, we have

f(1) = 2 × 1⁴ + 9 × 1³ + 6 × 1² – 11 × 1 – 6

= 2 + 9 + 6 – 11 – 6

= 17 – 17

= 0

Therefore,

(x – 1) is the factor of (2x⁴ + 9x³ + 6x² – 11x – 6)