Factorize:
x3 + y3 – 12xy + 64
We know that,
a3 + b3 + c3 – 3abc = (a + b + c) (a2 + b2 + c2 – ab – bc – ca)]
Using this formula, we get
= (x)3 + (y)3 + (4)3 – 3 (x) (y) (4)
= (x + y + 4) [(x)2 + (y)2 + (4)2 – (x) (y) – (y) (4) – (4) (x)]
= (x + y + 4) (x2 + y2 + 16 –xy – 4y – 4x)