Find the missing frequencies in the following frequency distribution, whose mean is 50.
X | 10 | 30 | 50 | 70 | 90 | Total |
Y | 17 | f1 | 32 | f2 | 19 | 120 |
Let’s draw the table and calculate the relative value of variables ∑xi×fi
(xi) | (fi) | (xi×fi) |
10 | 17 | 170 |
30 | f1 | 30f1 |
50 | 32 | 1600 |
70 | f2 | 70f2 |
90 | 19 | 1710 |
∑fi = 68 + f1 + f2 | ∑xi×fi = 3480 + 30f1 + 70f2 |
We have,
∑fi = 120 (given)
∑fi = 68 + f1 + f2 = 120
f1 + f2 = 120 - 68
f1 + f2 = 52…. Equation (i)
Now we have,
Mean = 50 (given)
Mean = = 50
50 =
50×68 + f1 + f2 = 3480 + 30f1 + 70f2
3400 + 50 f1 + 50f2 = 3480 + 30f1 + 70f2
50f1 - 30f1 + 50 f2 -70f2 = 3480 – 3400
20f1-20f2 = 80
20(f1-f2) = 80
f1-f2 = ……. Equation (ii)
by adding equation (i) and (ii) we get,
∑f1 = 56
From equation (ii)
f1-f2 = 4
28 – f2 = 4
f2 = 28-4 = 24
Hence missing frequencies are f1 = 28 and f2 = 24.