It is given that in ABCD, and
We know that opposite angles of parallelogram are equal.

∴∠A = ∠C and ∠B = ∠D
Also,

∠A + ∠B = 180° …Adjacent angles of parallelogram are supplementary
∴​ (2x + 25)°​ + (3x − 5)°​ = 180°
​5x° +20° = 180°
​ 5x° = 160°
​ x° = 32°
∴​∠A = 2 ⨯ 32 + 25 = 89°

∴ ∠B = 3 ⨯ 32 − 5 = 91°
Hence, x = 32°, ∠A = ∠C = 89° and ∠B = ∠D = 91°