Using the formula (a + b)2 = (a2 + 2ab + b2), evaluate:
(i) (310)2 (ii) (508)2
(iii) (630)2
(i) We know that,
(a + b)2 = (a2 + 2ab + b2)
We have,
3102 = (300 + 10)2
= [3002 + 2 (300 × 10) + 102]
= 90000 + 6000 + 100
= 96100
(ii) We know that,
(a + b)2 = (a2 + 2ab + b2)
We have,
5082 = (500 + 8)2
= [5002 + 2 (500 × 8) + 82]
= 250000 + 8000 + 64
= 258064
(iii) We know that,
(a + b)2 = (a2 + 2ab + b2)
We have,
6302 = (600 + 30)2
= [6002 + 2 (600 × 30) + 302]
= 360000 + 36000 + 900
= 396900