The angles of a pentagon are x°, (x + 20)°. (x + 40)°, (x + 60)° and (x + 80)°. The smallest angle of the pentagon is
The sum of interior angles of pentagon is
= (n – 2) × 180° [n is number of sides of polygon)]
= (5 – 2) X 180°
= 540°
x + (x + 20) + (x + 40) + (x + 60) + (x + 80) = 540
5x + 200 = 540
5x = 340
X = 340 / 5
= 68°
So, smallest angle of pentagon is 68°