The interior angle of a regular polygon exceeds its exterior angle by 108°. How many sides does the polygon have?
Let x be the exterior angle
Interior Angle = x + 108°
Interior Angle + Exterior Angle = 180°
X + (x + 108°) = 180°
2x= 180° - 108°
2x =72°
= 36°
So, Exterior Angle = 36°
No. of Sides = 360 / Exterior Angle
= 360 / 36
= 10