Determine the greatest 3-digit number exactly divisible by 8, 10 and 12.

Let’s take the LCM of 8, 10 and 12



LCM = 2 × 2 × 2 × 3 × 5 = 120


Now to get greatest 3-digit number we have to calculate the multiples of 120


120 × 1 = 120


120 × 2 = 240


120 × 3 = 360


120 × 4 = 480


120 × 5 = 600


120 × 6 = 720


120 × 7 = 840


120 × 8 = 960


120 × 9 = 1080


120 × 10 = 1200


Hence the greatest 3-digit number exactly divisible by 8, 10 and 12 is 960.

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