Find the equivalent fraction of 
having:
(a) denominator 20
(b) numerator 9
(c) denominator 30
(d) numerator 9
(a) 
3× 20 = 5× ….
3 × 2 × 2 × 5 = 5 × …
12 = …
Hence,
The required fraction is 
(b) 
3× … = 5× 9
5 × 3 × 3 = 3 × …
15 = …
Hence,
The required fraction is 
(c) 
3× 30 = 5× ….
3 × 2 × 3 × 5 = 5 × …
18 = …
Hence,
The required fraction is 
(d) 
3× … = 5× 27
5 × 3 × 3 × 3= 3 × …
45 = …
Hence,
The required fraction is 
11